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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+// Exa 5.13.3
+clc;
+clear;
+close;
+// Given data
+alpha_dc = 0.99;
+I_C = 6;// in mA
+I_C= I_C*10^-3;// in A
+I_CBO = 15;// in µA
+I_CBO= I_CBO*10^-6;// in A
+I_E = (I_C - I_CBO)/alpha_dc;// in A
+I_B = I_E - I_C;// in A
+disp(I_B*10^6,"The value of I_B in µA is");