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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+//Exa 3.10.5
+clc;
+clear;
+close;
+// Given data
+I=5;// in µA
+V=10;// in V
+T1= 0.11;// in °C^-1
+T2= 0.07;// in °C^-1
+// Io+I_R=I (i)
+// dI_by_dT= dIo_by_dT (ii)
+// 1/Io*dIo_by_dT = T1 and 1/I*dI_by_dT = T2, So
+Io= T2*I/T1;// in µA
+I_R= I-Io;// in µA
+R= V/I_R;// in MΩ
+disp(R,"The leakage resistance in MΩ is : ")