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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+// Exa 9.9
+clc;
+clear;
+close;
+// Given data
+m = 1;// in kg
+p = 10;// in bar
+p = p * 10^2;// in kpa
+x = 0.94;
+h_sen = 762.61;// in kJ/kg
+L = 2013.6;// in kJ/kg
+v_s = 0.1942;// in m^3 per kg
+w_ext = p * x * v_s * m;// in kJ/kg
+disp(w_ext,"The work done during evaporation in kJ/kg is");
+// Part (b)
+L_internal = (x * L) - w_ext;// in kJ/kg
+disp(L_internal,"Internal latent heat in kJ/kg is");
+// Part (c)
+U_wet = h_sen+x*L-p*x*v_s;// in kJ/kg
+disp(U_wet,"Internal energy in kJ/kg is");