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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+// Exa 3.1
+clc;
+clear;
+close;
+// Given data
+V_E= -0.7;// in V
+Bita=50;
+RC= 5;// in kΩ
+RE= 10;// in kΩ
+RE= RE*10^3;// in Ω
+RC= RC*10^3;// in Ω
+V_CC= 10;// in V
+V_BE= -10;// in volt
+I_E= (V_E-V_BE)/RE;// in A
+disp(I_E*10^3,"Emitter current in mA is : ")
+// I_E= I_B+I_C and I_C= Bita*I_B, so
+I_B= I_E/(1+Bita);// in A
+disp(I_B*10^6,"Base current in µA is : ")
+I_C= I_E-I_B;//in A
+disp(I_C*10^3,"Collector current in mA is : ")
+V_C= V_CC-I_C*RC;// in V
+disp(V_C,"The value of V_C in volts is :")