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authorpriyanka2015-06-24 15:03:17 +0530
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+clc
+clear
+//Input data
+A=14.5;//The air fuel ratio
+p2=0.825;//The pressure at the venturi throat in bar
+p1=1.013;//The atmospheric pressure in bar
+pd=37.5;//The pressure drop to the air cleaner in mm of Hg
+ma=260;//The mass flow rate of air in kg/h
+
+//Calculations
+pa=p1-p2;//Without air cleaner the depression at the throat in bar
+p21=p1-(pd/750)-pa;//The throat pressure when the air cleaner is fitted in bar
+pf=pa;//Pressure of fuel without air clesner in bar
+pf1=p1-p21;//Pressure of the fuel with air cleaner in bar
+Af=A*(pf/pf1)^(1/2);//Air fuel ratio with air cleaner
+
+//Output
+printf(' (a) The throat pressure when the air cleaner is fitted = %3.3f bar \n (b) The air fuel ratio with the air cleaner fitted = %3.2f ',p21,Af)