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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /2090/CH3/EX3.19 | |
| download | Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.gz Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.bz2 Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.zip | |
initial commit / add all books
Diffstat (limited to '2090/CH3/EX3.19')
| -rwxr-xr-x | 2090/CH3/EX3.19/Chapter3_Example19.sce | 21 |
1 files changed, 21 insertions, 0 deletions
diff --git a/2090/CH3/EX3.19/Chapter3_Example19.sce b/2090/CH3/EX3.19/Chapter3_Example19.sce new file mode 100755 index 000000000..09ae29d7f --- /dev/null +++ b/2090/CH3/EX3.19/Chapter3_Example19.sce @@ -0,0 +1,21 @@ +clc
+clear
+//Input data
+p=1;//Initial pressure in atm
+T=300;//Initial temperature in K
+Tc=2400;//To calculate the molefraction of the products at this temperature in K
+KP1=3.866;//Natural logarithm of equilibrium constant at 2400 K for the equation
+
+//Calculations
+K1=exp(KP1);//The value of equilibrium constant at 2400 K
+nr=1+0.5;//The number of moles of reactants
+Pp=(p*Tc)/(nr*T);//Pressure exercted on the products side per mole in atm/mole
+a=0.098;//The dissociation of 1 mole of CO2
+np=(a+2)/2;//The number of moles of products
+xco=[2*(1-a)]/(2+a);//Mole fraction of CO2
+xc=[2*a]/(2+a);//Mole fraction of CO
+xo=a/(2+a);//Mole fraction of O2
+PP=5.333*np;//Pressure of the product in bar
+
+//output
+printf('Mole fraction of the carbondioxide is %3.4f \n Mole fraction of the carbonmonoxide is %3.4f \n Mole fraction of oxygen is %3.4f \n Pressure of the product is %3.3f bar',xco,xc,xo,PP)
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