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diff --git a/2090/CH2/EX2.10/Chapter2_example10.sce b/2090/CH2/EX2.10/Chapter2_example10.sce
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+clc

+clear

+//Input data

+p1=1//Inlet pressure in bar

+T1=27+273//Temperature in K

+p2=4//pressure at point 2 in bar

+p3=16//Maximum pressure in bar

+Cv=0.573//specific heat at constant volume for gas in kJ/kgK

+Cp=0.761//specific heat at constant pressure for gas in kJ/kgK

+

+//Calculations

+g=(Cp/Cv)//Adiabatic index

+T2=(T1*(p2/p1)^((g-1)/g))//Temperature in K

+T3=(p3/p2)*T2//Temperature in K

+T4=T3*(p1/p3)^((g-1)/g)//Temperature in K

+Q1=Cv*(T3-T2)//Heat supplied in kJ/kg

+Q2=Cp*(T4-T1)//Heat rejected in kJ/kg

+W=Q1-Q2//Workdone in kJ/kg

+n=(W/Q1)*100//Efficiency of cycle 

+r=(p2/p1)^(1/g)//Compression ratio

+R=(Cp-Cv)//Universal gas constant in kJ/kg.K

+Vs=(R*1000*T1*(r-1))/(p1*10^5*r)//Swept volume in m^3/kg

+pm=(W/(Vs*100))//Mean effective pressure in bar

+

+//Output

+printf('(a) The work done per kg of gas is %3.1f kJ/kg \n (b) The efficiency of the cycle is %3.1f percent \n (c) Mean effective pressure is %3.2f bar',W,n,pm)