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authorpriyanka2015-06-24 15:03:17 +0530
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+//example 2.6
+//calculate Average depth of water applied
+clc;
+//Given
+L=100;//length of furrow
+W=1;//furrow spacing
+s=0.3//longitudnal slope of furrow
+t1=80//initial time flow of stream
+t2=35//final time flow of stream
+qm=0.6/s;
+q=qm*0.4;
+dav=((q*t2*60)+(2*t1*60))/100;
+mprintf("Average depth of water applied=%f mm.",dav);