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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+
+
+//example 2.1
+//calculate time required to cover 0.1 hectare area by tubewell
+clc;
+//Given
+Q=0.0108, //discharge through well
+y=0.075, //average depth of flow
+I=0.05, //average infiltration rate
+A=0.1, //area to cover
+t=(60*2.303*y*log10(Q/(Q-I*A)))/I,
+t=round(t);
+mprintf("Time required to cover given area=%f minutes.",t);