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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+clc
+clear
+//Input data
+P1=1;//Initial pressure in bar
+P3=9;//Final pressure in bar
+n=1.3;//Compression index
+
+//Calculations
+W1=(n/(n-1))*(P1*10^5*(((P3/P1)^((n-1)/n))-1));//Work done in compression in a single stage per unit volume per kg of air in N m
+P2=(P1*P3)^(0.5);//Intercooler pressure for perfect intercooling in bar
+W2=2*(n/(n-1))*(P1*10^5*(((P2/P1)^((n-1)/n))-1));//Work done in compression in a two stage compressor per unit volume per kg of air in N m
+Wc=W1-W2;//Saving in work of compression in N m
+nw=((W1-W2)/W1)*100;//Percentage saving in work of compression in percentage
+
+//Output
+printf('Percentage saving in the work of compression of air in two stages instead of single stage is %3.2f percent',nw)