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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+// Solution of Aryabhatta's identity Eq. 11.8, as discussed in Example 11.3 on page 409.
+// 11.3
+
+exec('xdync.sci',-1);
+exec('rowjoin.sci',-1);
+exec('polsize.sci',-1);
+exec('left_prm.sci',-1);
+exec('t1calc.sci',-1);
+exec('indep.sci',-1);
+exec('seshft.sci',-1);
+exec('makezero.sci',-1);
+exec('move_sci.sci',-1);
+exec('colsplit.sci',-1);
+exec('clcoef.sci',-1);
+exec('cindep.sci',-1);
+
+C = [1 0.5]; dC = 1; j=2;
+A = [1 -0.6 -0.16]; dA = 2;
+zj = zeros(1,j+1); zj(j+1) = 1;
+[Fj,dFj,Ej,dEj] = xdync(zj,j,A,dA,C,dC)