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authorpriyanka2015-06-24 15:03:17 +0530
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+// Chapter6
+// Page.No-238
+// Example_6_16_a
+// Design of differentiator
+// Given
+clear;clc;
+C1=0.1*10^-6; // Assume
+fa=1*10^3; // Freq at which gain is 0 dB
+Rf=1/(2*%pi*fa*C1); // Using fa=1/(2*%pi*Rf*C1)
+printf("\n Feedback resistance is = %.1f ohm \n",Rf)
+Rf=1.5*10^3; // Approximation
+fb=20*10^3; // Gain limiting freq
+R1=1/(2*%pi*fb*C1);
+printf("\n Resistance,R1 is = %.1f ohm \n",R1)
+R1=82; // Approximation
+Cf=R1*C1/Rf;
+printf("\n Capacitance,Cf is = %.10f farad \n",Cf)
+Cf=0.005*10^-6; // Approximation \ No newline at end of file