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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /1964/CH5/EX5.38 | |
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-rwxr-xr-x | 1964/CH5/EX5.38/ex5_38.sce | 19 |
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diff --git a/1964/CH5/EX5.38/ex5_38.sce b/1964/CH5/EX5.38/ex5_38.sce new file mode 100755 index 000000000..f164fa649 --- /dev/null +++ b/1964/CH5/EX5.38/ex5_38.sce @@ -0,0 +1,19 @@ +//Chapter-5, Example 5.38, Page 199
+//=============================================================================
+clc
+clear
+//INPUT DATA
+Q=45;//quality factor
+f1=600*10^3;//freq in Hz
+f2=1000*10^3;//freq in Hz
+//given new resistance is 50% greater than former.let us consider two reistances as R1=1 ohm and R2=1.5 ohm for ease of calculation.Then
+R1=1;//resistance in ohm
+R2=1.5;//resistance in ohm
+//CALCULATIONS
+W1=2*%pi*f1;//angular freq 1 in rad/sec
+W2=2*%pi*f2;//angular freq 2 in rad/sec
+Q=45;//quality factor
+L=(Q*R1)/(W1);//inductance in henry
+Q1=(W2*L)/(R2);//new quality factor
+mprintf("Thus new quality factor is %d",Q1);
+//=================================END OF PROGRAM======================================================================================================
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