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+//Chapter-5, Example 5.28, Page 189

+//=============================================================================

+clc

+clear

+//INPUT DATA

+f=50;//freq in hz

+V=100;//volatge in V

+L1=0.015;//inductance in branch 1 in henry

+L2=0.08;//inductance in branch 2 in henry

+R1=2;//resistance of branch 1 in ohms

+x1=4.71;//reactance of branch 1 in ohms

+R2=1;//resistance of branch 2 in ohms

+x2=25.13;//reactance of branch 2 in ohms

+Z1=(R1)+(%i*x1);//impedance of branch1 in ohms

+Z2=(R2)+(%i*x2);//impedance of branch1 in ohms

+I1=V/Z1;//current in branch 1 in A

+printf("current in branch 1 in A")

+disp(I1);

+I2=V/Z2;//current in branch 2 in A

+printf("current in branch 2 in A")

+disp(I2);

+I3=I1+I2;//total current in A

+printf("total current in A")

+disp(I3);

+//note:Answer for real part of total current given in textbook is wrong.Please check the calculations

+//=================================END OF PROGRAM======================================================================================================