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+//Chapter-3, Example 3.10, Page 113
+//=============================================================================
+clc
+clear
+//INPUT DATA
+NA=15000;//no of turns in coil A
+IA=6;//current in coil A in Amp(A)
+phiA=0.05*10^-3;//flux in coil A in wb
+NB=12000;//no of turns in coil B
+IB=6;//current in coil B in Amp(A)
+phiB=0.08*10^-3;//flux in coil B in wb
+phiAB=0.55*0.05*10^-3;//mutual flux in wb
+//CALCULATIONS
+LA=phiA*NA/IA;//self inductance of coil A in H
+LB=phiB*NB/IB;//self inductance of coil B in H
+LAB=phiAB*NB/IB;//mutual inductance of coils in H
+K=LAB/sqrt(LA*LB);//coefficient of coupling
+//OUTPUT
+mprintf("Thus the self inductance of coil A is %1.3f H\n",LA);
+mprintf("Thus the self inductance of coil B is %1.2f H \n",LB);
+mprintf("Thus the mutual inductance of coils is %1.3f H \n",LAB);
+mprintf("Thus the coefficient of coupling is %1.3f \n",K)
+
+//=================================END OF PROGRAM==============================