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+//Chapter-2, Example 2.6, Page 93

+//=============================================================================

+clc;

+clear;

+//INPUT DATA

+l1=0.1;//length in m

+l2=0.18;//length in m

+l3=0.18;//length in m

+lg=1*10^-3;//airgap length in mm

+a1=6.25*10^-4;//area in m^2

+a2=3*10^-4;//area in m^2

+ur=800;//relative permeability of iron path

+ur2=1;//relative permeability in free space

+u0=4*%pi*10^-7

+N=600;

+phi=10^-4;//airgap flux in Wb

+//CALCULATIONS 

+//for the airgap

+Bg=(phi/(a1));//fluxdensity in Tesla

+Hg=(Bg/(u0*ur2));//magnetising force in A/m

+MMF1=Hg*lg;//in A

+//for path I1

+B1=0.16;// flux density in tesla

+H1=(B1/(ur*u0));//magnetising force in A/m

+MMF2=H1*l1;//in A

+//since paths l2 and l3 are similar,the total flux divide equally between these two paths.Since these paths are in parallel,consider only one of them

+//for path l2

+flux=50*10^-6;//flux in wb

+B2=(flux/a2);//fluxdensity in tesla

+H2=(B2/(ur*u0));//magnetising force in A/m

+MMF3=H2*l2;//in A

+totalmmf=MMF1+MMF2+MMF3;//in A

+I=(totalmmf/N);//current required in A

+//OUTPUT

+mprintf("Thus current required is %1.3f A",I);

+ //=================================END OF PROGRAM==============================