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+//Chapter-15, Example 15.8, Page 498

+//=============================================================================

+clc

+clear

+//CALCULATIONS

+//using 1's complement method

+x1=base2dec(['1000'],2)//converting binary to decimal

+x=bin2dec('1010')

+x2=dec2bin(bitcmp(x,4))//1's complement of a number

+disp(x2)

+x3=base2dec([x2],2)

+x4=x1+x3;

+x5=dec2base(x4,2)//converting decimal to hexadecimal

+disp(x5)

+y=15;

+z=bitand(x4,y);//eliminating carry

+z2=dec2base(z,2)//converting decimal to binary

+disp(z2)

+//using normal method

+a=base2dec(['1000','1010'],2);//converting binary to decimal

+b=a(2)-a(1);//subtraction

+c=dec2base(b,2)//converting decimal to binary

+disp(c);//since we cannot use dec2base for negative integers,we cannot do (a(1)-a(2)) but we can do (a(2)-a(1)),with '-' sign added before the result.hence 'c' here is actually -'c'

+//=================================END OF PROGRAM=======================================================================================================