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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /1964/CH12/EX12.7/ex12_7.sce | |
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initial commit / add all books
Diffstat (limited to '1964/CH12/EX12.7/ex12_7.sce')
| -rwxr-xr-x | 1964/CH12/EX12.7/ex12_7.sce | 19 |
1 files changed, 19 insertions, 0 deletions
diff --git a/1964/CH12/EX12.7/ex12_7.sce b/1964/CH12/EX12.7/ex12_7.sce new file mode 100755 index 000000000..6dc1715bc --- /dev/null +++ b/1964/CH12/EX12.7/ex12_7.sce @@ -0,0 +1,19 @@ +//Chapter-12, Example 12.7, Page 346
+//=============================================================================
+clc
+clear
+//INPUT DATA
+V=230;//AC supply voltage
+f=50;//frequency in Hz
+noofturns=4;//noofturns ratio
+Rl=600;//load resistance in ohms
+//CALCULATIONS
+Vrms=(V/4);//rms value of secondary voltage in V
+Vm=sqrt(2)*(Vrms);//max value of secondary voltage
+Vdc=(2*Vm)/(%pi);//DC output voltage
+Pdc=(Vdc)^2/(Rl);//DC power in W
+PIV=Vm;//PIV across each diode in V
+f0=2*f;//output frequency in Hz
+mprintf("Thus DC output voltage,DC power,PIV and output frequency are %1.0f V,%1.3f W,%2.1f V and %d hz respectively",Vdc,Pdc,PIV,f0);
+//note:in given problem,Rl is 600 ohms,but in textbook calculations Rl taken is 1000 ohms,I took Rl as 600 ohms
+//=================================END OF PROGRAM======================================================================================================
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