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authorpriyanka2015-06-24 15:03:17 +0530
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+//Chapter-12, Example 12.1, Page 341
+//=============================================================================
+clc
+clear
+//INPUT DATA
+Vm=325;//voltage in volts
+Rl=1000;//resistive load in ohms
+rf=100;//forward resistance in ohms
+//CALCULATIONS
+//for subdivision (a)
+Im=Vm/(rf+Rl);//peak value of current in A
+Idc=Im/(%pi);//average current in A
+Irms=Im/2;//rms value of current in A
+mprintf("Thus peak value of current,average current and rms value of current are %g A ,%g A and %g A respectively\n",Im,Idc,Irms);
+//for subdivision (b)
+Pdc=(Idc)^2*(Rl);//DC power output
+mprintf("Thus DC power is %1.3f W\n",Pdc);
+//for subdivision (c)
+Pac=(Irms)^2*(rf+Rl);//AC input power
+mprintf("Thus AC power is %d W\n",Pac);
+//for subdivision (d)
+n=(Pdc/Pac);//efficiency of rectification
+n=n*100;//efficiency in percentage
+mprintf("Thus efficiency in percentage is %2.2f percentage",n);
+//=================================END OF PROGRAM======================================================================================================