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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /1955/CH5/EX5.3/example3.sce | |
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initial commit / add all books
Diffstat (limited to '1955/CH5/EX5.3/example3.sce')
| -rwxr-xr-x | 1955/CH5/EX5.3/example3.sce | 43 |
1 files changed, 43 insertions, 0 deletions
diff --git a/1955/CH5/EX5.3/example3.sce b/1955/CH5/EX5.3/example3.sce new file mode 100755 index 000000000..1a04b3ce5 --- /dev/null +++ b/1955/CH5/EX5.3/example3.sce @@ -0,0 +1,43 @@ +clc
+clear
+//input data
+P1=5//Input pressure of steam in bar
+P2=3//Exhaust pressure of steam in bar
+C0=75//Carry over velocity of steam in m/s
+a1=20//Nozzle angle in degree
+UC1=0.4//The direction of blade rotation and blade speed ratio
+b2=20//Blade exit angle in degree
+m=2.5//Steam flow rate in kg/s
+W=206//Power Output of the stage in kW
+Nn=0.9//Efficiency of the nozzle
+
+printf('Assuming isentropic expansion the enthalpy drop can be found from steam table\n\nThe following values are obtained from steam tables')
+
+h1=2747.5//Enthalpy at initial pressure in kJ/kg
+s1=6.819//Entropy at initial pressure in kJ/kg.K
+s2=s1//Entropy at final pressure in kJ/kg.K
+sfp2=1.647//Entropy of fliud at final pressure in kJ/kg.K
+sfgp2=5.367//Entropy of fliud-gas mixture at final pressure in kJ/kg.K
+hfg=2170.1//Enthalpy of fliud-gas mixture in kJ/kg
+hf=551.5//Enthalpy of fliud in kJ/kg
+
+printf('\n\nThe scale of the velocity vector diagram is 1:50\n\nThe following values are obtained from the velocity vector diagram')
+
+W1=280//Relative velocity at inlet in m/s
+W2=240//Relative velocity at exit in m/s
+
+//calculations
+x2=(s2-sfp2)/sfgp2//The percentage of wet steam
+h2s=hf+(x2*hfg)//The isentropic enthalpy at the second stage in kJ/kg
+dhs=h1-h2s//Isentropic heat drop in kJ/kg
+C1=((2000*Nn*dhs)+(C0^2))^(1/2)//Velocity of steam at exit from nozzle in m/s
+U=UC1*C1//Blade speed in m/s
+Wx1Wx2=(W*10^3)/(m*U)//The sum of whirl components of velocity in m/s
+Ndia=(U*Wx1Wx2)/((C1^2)/2)//Diagram efficiency
+RV=W2/W1//Relative velocity ratio
+E=dhs+((C0^2)/2000)//Energy supplied per kg in kJ/kg
+Ns1=(U*Wx1Wx2)/(E*10^3)//Stage efficiency
+Ns2=Ndia*Nn//Stage efficiency in other method
+
+//output
+printf('\n\n(a)Velocity of steam at exit from nozzle is %3.2f m/s\n(b)Diagram efficiency is %3.4f\n(c)Relative velocity ratio is %3.3f\n(d)\n Stage efficiency in method 1 is %3.4f\n Stage efficiency in method 2 is %3.4f',C1,Ndia,RV,Ns1,Ns2)
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