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authorpriyanka2015-06-24 15:03:17 +0530
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+//Chapter-6,Example 6_18_2,Page 6-38
+clc()
+
+//Given Values:
+u0=4*%pi*10^-7 //Permeability in vacuum
+ur=380 //Relative permeability
+d=20*10^-2 //diameter of solenoid in m
+r=d/2 //radius of ring in m
+A=5*10^-4 //Crosss sectional area of ring in m^2
+phi=2*10^-3 //flux in weber
+N=200 //Number of turns
+
+//Calculations:
+l=%pi*d //air gap in the ring
+S=(l/(u0*ur*A)) //Reluctance of iron ring
+printf('Reluctance of iron ring is =%.2f Amp-turn per Wb \n \n',S)
+
+//ohm's law for magnetic circuit is phi=N*I/S. thus,
+I=S*phi/N //required current
+printf(' Current required to obtain given magnetic flux is =%.2f Amperes \n',I)