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authorpriyanka2015-06-24 15:03:17 +0530
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+//Chapter-3,Example 3_13,Page 3-23
+clc()
+
+//Given Data:
+n1=1.5 //R.I. of core
+delta=0.0005 //Fractional index difference
+
+//Calculations:
+//(a):
+//Delta=(u1-u2)/u1
+n2=n1-(n1*delta) //R.I. of cladding
+printf('(a)Refractive Index of cladding of fibre is =%.2f \n \n',n2)
+
+//(b):
+phi=asin(n2/n1)*180/%pi //Critical internal reflection angle
+printf(' (b)Critical internal reflection angle of Fibre is =%.1f degrees \n \n',phi)
+
+//(c):
+theta0=asin(sqrt(n1^2-n2^2))*180/%pi //External critical Acceptance angle
+printf(' (c)External critical Acceptance angle of Fibre is =%.2f degrees \n \n',theta0)
+
+//(d):
+NA=n1*sqrt(2*delta) //Formula to find Numerical Aperture
+printf(' (d)Numerical Aperture of Fibre is =%.4f \n',NA)