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authorpriyanka2015-06-24 15:03:17 +0530
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+//Chapter-3,Example 3_11_1,Page 3-25
+clc()
+
+//Given Data:
+u1=1.52 //R.I. of Core
+u2=1.5189 //R.I.of Cladding
+lam=1.3*10^-6 //wavelength in meter
+d=29*10^-6 //core diameter in meter
+a=d/2
+
+//Calculations:
+NA=sqrt(u1^2-u2^2) //Formula to find Numerical Aperture
+V=2*%pi*a*NA/lam //Normalised frequency
+Nm=(V^2)/2 //Number of modes
+
+printf('Normalised frequency of Fibre is (V)=%.3f \n \n',V)
+printf(' The Maximum Number of modes the Fibre will support is (Nm) =%.0f \n',Nm)