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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+
+clc
+clear
+//Input data
+CV=24;//The calorific value of the fuel in MJ/kg
+C=0.65;//The amount of calorific value released in the bed in %
+to=850;//Temperature at which products leave in degree centigrade
+ti=30;//The inlet temperature in degree centigrade
+tb=850;//The bed temperature in degree centigrade
+A=14.5;//The air fuel ratio by mass
+Cp=1.035;//The specific heat of the products leaving the bed surface in kJ/kgK
+B=7000;//The burning rate of coal in kg/h
+
+//Calculations
+H=(C*CV*1000)-(A*Cp*(to-ti));//Heat removal from the bed per kg fuel in kJ/kg fuel
+Hr=(H*B)/3600;//Rate of heat removal from the bed in kW
+Hb=(B/3600)*(1-C)*CV*1000;//The rate of heat removal from the above bed zone in kW
+
+//Output
+printf('(a) The rate of heat removal from the bed = %3.0f kW \n (b) The rate of heat removal from the above bed zone = %3.0f kW ',Hr,Hb)