initial commit / add all books

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+
+clc

+clear

+//Input data

+CO2=13.2;//The volume of carbondioxide present in the partial analysis of dry flue gas in %

+O2=3.2;//The volume of oxygen present in the partial analysis of dry flue gas in %

+C=88;//The mass of carbon present in the coal according to coal analysis on mass basis in %

+H=4.4;//The mass of hydrogen present in the coal according to coal analysis on mass basis in %

+A=7.6;//The mass of ash present in the coal according to coal analysis on mass basis in %

+M=0;//Moisture present in the fuel was nil

+Mc=12;//Molecular weight of the carbon 

+Mh=2;//Molecular weight of the hydrogen

+Mo=32;//Molecular weight of the oxygen

+Mho=18;//Molecular weight of water

+p=101.325;//Atmospheric pressure in kPa

+

+//Calculations

+c=C/Mc;//Equating coefficients of the carbon from the equation 

+g=H/Mh;//Equating coefficients of the hydrogen from the equation 

+x=(CO2/100)/(O2/100);//From dry fuel gas analysis (dfg) 

+d=[[(CO2/100)*(47.5)]-7.333]/[[(CO2/100)*(3.032)]-1];//Coefficient of the carbonmonoxide in the equations product side

+b=c-d;//Coefficient of the carbondioxide in the equation product side

+a=10.21-(0.742*d);//Coefficient of the oxygen in the reactant side of the equation 

+e=b/x;//Coefficient of the oxygen in the product side of the equation 

+f=3.76*a;//Equating coefficients of the nitrogen from the equation 

+ma=(a*Mo)/0.232;//Mass of air supplied for 100 kg coal in kg

+ma1=ma/100;//Mass of air supplied per kg coal in kg

+T=b+d+e+f;//Total number of moles of dry flue gas (dfg)

+CO21=(b/T)*100;//Carbondioxide by volume in percentage

+O21=(e/T)*100;//Oxygen by volume in percentage

+CO1=(d/T)*100;//Carbonmonoxide by volume in percentage

+N21=(f/T)*100;//Nitrogen by volume in percentage

+Mwv=(g*Mho)/100;//Mass of watervapour formed per kg coal in kg

+Mf=(g)/(b+d+e+f+g);//Mole fraction of water vapour in flue gas

+P=Mf*p;//Partial pressure of water vapour in kPa

+D=32.9;//Dew point temperature from steam tables in degree centigrade

+

+//Output

+printf('(a)The complete volumetric composition of the dry flue gas is \n Carbondioxide by volume = %3.2f percentage \n Oxygen by volume = %3.2f percentage \n Carbonmonoxide by volume = %3.2f percentage \n Nitrogen by volume = %3.2f percentage \n (b) The actual amount of air supplied per kg coal = %3.2f kg \n (c) Mass of water vapour formed per kg coal = %3.2f kg \n (d) The dew point temperature of the flue gas = %3.2f degree centigrade ',CO21,O21,CO1,N21,ma1,Mwv,D)