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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+clc,clear
+printf('Example 6.6\n\n')
+//note that a new function p2z has been defined below for direct representation of complex numbers in polar form
+function [FUN] = p2z(RRRR,Theeeta)
+ FUN = RRRR.*exp(%i*%pi*Theeeta/180.);
+endfunction
+
+V_l=10*10^3
+V_ph=V_l/sqrt(3)
+R_a=0.4
+Z=complex(R_a,6)
+I_a=p2z(300,-acosd(0.8))
+E=V_ph+I_a*Z
+
+phi=acos(0.8)
+alternator_op_ph=V_ph*abs(I_a)*cos(phi) //Power delivered to infinite bus per phase
+
+//Power deliered to the altrernator = Power delivewred to bus bar + I^2*R losses in armature
+alternator_power= alternator_op_ph+ abs(I_a)^2*R_a
+
+//this power developed remains constant.change pf to 1 and calculate corresponding armature current
+//alternator_power=V_ph*I_a1*cos(phi1)+I_a1^2*0.4
+//solve the quadratic equation 0.4 I_a1^2+5773.50 I_a1- 1421640 =0
+I_a1=(-1*V_ph+sqrt(V_ph^2-4*R_a*-1*alternator_power))/(2*R_a)
+
+//also as follows
+E1=V_ph+I_a1*Z
+decrease=100*(abs(E)-abs(E1))/abs(E)
+printf('Percentage decrease in induced e.m.f is %.1f percent',decrease)