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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+clc,clear
+printf('Example 6.15\n\n')
+
+V_L=6*10^3
+V_ph=V_L/sqrt(3)
+VA=2000*10^3
+I_FL=VA/(sqrt(3)*V_L) ,I=I_FL
+
+X_s=1.2,R_a=0.01 //both per unit
+IR_a=(1/100)*V_ph //product of I and R_a
+R_a=IR_a/I_FL
+IX_s=(120/100)*V_ph //product of I and X_s
+//IX_s=(12/100)*V_ph // this is the mistake made in the textbook
+X_s=IX_s/I_FL
+
+//at full load and 0.8 pf
+phi=acos(0.8)
+//V_ph=complex(V_ph*cos(phi),V_ph*sin(phi)) //just introduced the angle
+E_ph=sqrt( (abs(V_ph)*cos(phi)+ IR_a)^2+ (abs(V_ph)*sin(phi)+ IX_s)^2 )
+Poles=8,f=50
+
+delta=asin( (abs(V_ph)*sin(phi)+IX_s)/E_ph) -phi
+delta_dash_mech=(%pi/180) //displacemnt in degree mechanical
+//displacemnt in degree electrical
+delta_dash_elec=delta_dash_mech*(Poles/2)
+P_SY=abs(E_ph)*abs(V_ph)*cos(delta)*sin(delta_dash_elec)/X_s //synchronising power per phase
+P_SY_total=3*P_SY //total synchronising power
+
+ns=120*f/(60*Poles) //in r.p.s
+T_SY=P_SY_total/(2*%pi*ns) //Synchronising torque
+
+printf('Synchronising power is %.2f kW\n',P_SY_total/1000)
+printf('Synchronising torque is %.2f N-m',T_SY)
+
+printf('\n\nNote that answer obtained doesnt match with textbook due to the following reasons: \n(i)IX_s is considered wrong in textbook.\nIt should have been 4156.92(instead of 415.692) \nTo verify this use commented statement of IX_s (line 13)and notice that it matches with textbook ans then' )