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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+clc,clear
+printf('Example 3.17\n\n')
+
+V=500
+R_a=0.22,R_sh= 250//armature resistance and shunt field resistance
+I=5 //no load current
+motor_input_NL=V*I //no load motor input
+I_sh=V/R_sh
+I_a_NL= I- I_sh //no load armature current
+arm_cu_loss_NL = R_a*I_a_NL^2 //no load armature copper loss
+constant_loss = motor_input_NL - arm_cu_loss_NL
+
+//When motor draws 100 A current
+I=100
+I_a = I - I_sh
+arm_cu_loss =R_a* I_a^2 //armature copper loss
+total_losses = arm_cu_loss + constant_loss
+motor_input = V*I
+motor_output = motor_input -total_losses
+eta_m=100*(motor_output/motor_input) //motor efficiency
+printf('(i)Efficiency of motor at 100 A current is %.2f percent \n',eta_m)
+
+//part(b)
+E_b_NL= V- I_a_NL*R_a //back emf at no load
+E_b= V- I_a*R_a //back emf at 100 A
+//E_b is proportional to N.. and using componendo dividendo
+speed_change= 100*((E_b_NL - E_b)/E_b)
+printf('(ii)Percentage change in speed = %.3f percent\n\n',speed_change)
+
+
+printf('Note that the following were assumptions made\n')
+printf('(i) Due to heating , resistance of shunt field winding will be increased which will reduce the shunt field current.This will decrease the flux which is neglected\n')
+printf('(ii) Though the motor speed is changing from no load to given load , the mechanical losses are assumed to be cosnstant\n')
+printf('(iii)The effect of armature reaction aon main pole flux and its effect on iron loss is neglected')