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authorpriyanka2015-06-24 15:03:17 +0530
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+
+// Theory and Problems of Thermodynamics
+// Chapter 9
+// Air_water Vapor Mixtures
+// Example 13
+
+clear ;clc;
+
+//Given data
+mw3 = 1000 // cooling tower supply rate in kg/min
+T1 = 303.15 // Temp of air entering cooling tower in K
+RH1 = 0.3 // relative humidity of air entering cooler
+T2 = 308.15 // Temp of air leaving cooling tower in K
+RH2 = 0.8 // relative humidity of air leaving cooler
+T3 = 318.15 // Temp of water entering cooling tower in K
+T4 = 300.15 // Temp of water leaving cooling tower in K
+
+// subscript 1 and 2 denotes the state of air entering and leaving the cooling tower respectively
+// subscript 3 and 4 denotes the state of water entering and leaving the cooling tower respectively
+
+// data from psychometric chart for T = 30 degree C and RH = 0.3
+SH1 = 0.0078 // in kg H2O/kg air
+h1 = 51 // in kJ/kg air
+// data from psychometric chart for T = 35 degree C and RH = 0.8
+SH2 = 0.029 // in kg H2O/kg air
+h2 = 110 // in kJ/kg air
+hw3 = 188.45 // in kJ/kg
+hw4 = 113.25 // in kJ/kg
+
+// mass balance for H2O:
+//mw3-mw4 = ma*(SH2-SH1)
+
+// energy balance gives:
+// mw3*hw3 - mw4*hw4 = ma*(h2-h1)
+
+// x(1) = ma; x(2)= mw4;
+function[f] =F(x)
+ f(1) = mw3-x(2)-x(1)*(SH2-SH1);
+ f(2) = mw3*hw3 - x(2)*hw4 -x(1)*(h2-h1);
+endfunction
+x = [10 10];
+y = fsolve(x,F)
+
+ma = y(1); // air flow rate in kg/min
+mw4 = y(2);
+
+wat_mak = mw3-mw4; // make up water required
+
+// Output Results
+mprintf('Make up water required = %4.2f kg/min' , wat_mak);
+mprintf('\n Air flow rate = %4.1f kg/min' , ma);