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| author | priyanka | 2015-06-24 15:03:17 +0530 |
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| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /1919/CH5/EX5.3 | |
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Diffstat (limited to '1919/CH5/EX5.3')
| -rwxr-xr-x | 1919/CH5/EX5.3/Ex5_3.sce | 23 |
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diff --git a/1919/CH5/EX5.3/Ex5_3.sce b/1919/CH5/EX5.3/Ex5_3.sce new file mode 100755 index 000000000..55f9e6099 --- /dev/null +++ b/1919/CH5/EX5.3/Ex5_3.sce @@ -0,0 +1,23 @@ +
+// Theory and Problems of Thermodynamics
+// Chapter 5
+// Second law of Thermodynamics
+// Example 3
+
+clear ;clc;
+
+//Given data
+TL = -10 //TL = Lower temperature of reservoir
+TH = 40 //TH = High temperature of reservoir
+
+// Units conversion from Celsius to Kelvin
+TL = TL + 273.15;
+TH = TH + 273.15;
+
+// To find the coefficient of performance of a Carnot refrigerator and a Carnot Heat Pump
+COP_R = TL/(TH-TL); // Carnot refrigerator
+COP_HP = TH/(TH-TL); // Carnot Heat pump
+
+// Results
+mprintf('The coefficient of performance of a Carnot refrigerator = %5.3f ', COP_R)
+mprintf('\n The coefficient of performance of a Carnot Heat Pump = %5.3f ', COP_HP)
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