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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /1919/CH5/EX5.20/Ex5_20.sce | |
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initial commit / add all books
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| -rwxr-xr-x | 1919/CH5/EX5.20/Ex5_20.sce | 26 |
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diff --git a/1919/CH5/EX5.20/Ex5_20.sce b/1919/CH5/EX5.20/Ex5_20.sce new file mode 100755 index 000000000..2e5665e8f --- /dev/null +++ b/1919/CH5/EX5.20/Ex5_20.sce @@ -0,0 +1,26 @@ +
+// Theory and Problems of Thermodynamics
+// Chapter 5
+//Second Law of Thermodynamcis
+// Example 20
+
+clear ;clc;
+
+//Given data
+P1 = 0.5 // entering pressure of air at nozzle in MPa
+T1 = 500 // entering temperature of air at nozzle in K
+V1 = 2 // velocity of air enters at nozzle
+P2 = 0.1 // leaving pressure of air from nozzle in MPa
+r = 1.4 // ratio of specific heats of air
+R = 8.314 // gas constant
+
+T2 = T1*(P2/P1)^((r-1)/r) // enthalphy for superheated steam kJ/kg
+// from law of thermodynamics
+//(V2^2)/2 = h1 + (V1^2)/2 - h2
+//(V2^2)/2 = cp*(T1-T2) + (V1^2)/2
+
+deff('y=mass(V2)', 'y = (V2^2)/2 - (R*r/(r-1))*(T1-T2) + (V1^2)/2')
+V2 = fsolve(0,mass) // Mass of water vaporised in kg
+
+// Output Results
+mprintf('The exit velocity of air = %5.2f m/s', V2)
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