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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /1910/CH11/EX11.3/Chapter113.sce | |
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-rwxr-xr-x | 1910/CH11/EX11.3/Chapter113.sce | 21 |
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diff --git a/1910/CH11/EX11.3/Chapter113.sce b/1910/CH11/EX11.3/Chapter113.sce new file mode 100755 index 000000000..ad2c4a0be --- /dev/null +++ b/1910/CH11/EX11.3/Chapter113.sce @@ -0,0 +1,21 @@ +// Display mode
+mode(0);
+// Display warning for floating point exception
+ieee(1);
+clear;
+clc;
+disp("Introduction to heat transfer by S.K.Som, Chapter 11, Example 3")
+disp("The view factors F13 and F31 between the surfaces 1 and 3 are ")
+//Determine the view factors F13 and F31 between the surfaces 1 and 3.
+//F1-2,3=F12+F13
+//So F13=F1-2,3-F12
+//Let F1-2,3=F123
+//From Radiation Shape factor b/w two perpendicular rectangles with a commom edge table we get F12=.027,F1-2,3=0.31
+F123=0.31;//View factor
+F12=.27;//View factor
+F13=F123-F12//View factor
+//A1,A2 and A3 are the emitting surface areas
+//From reciprocity relation F31=(A1/A3)/F13
+A1=2;
+A3=2.5;
+F31=(A1/A3)*F13
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