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+//We have quadratic equation x^2-2*x-8=0 with roots -2 and 4

+//for solving it we use fixed point iteration method for that we rearrange it in 3 ways.

+//first way x=(2*x+8)^(1/2)

+//here x0 is chosen arbitrarily

+

+clear;

+clc;

+close();

+format('v',5)

+funcprot(0);

+deff('[fixed_point]=fx(x)','fixed_point=(2*x+8)^0.5')

+x0=5;

+while abs(x0-fx(x0))>0.5*10^(-2)

+  x0=fx(x0);

+end

+disp(x0,'root is :')

+

+//second way x=(2*x+8)/x

+

+format('v',5)

+funcprot(0);

+deff('[fixed_point]=fx(x)','fixed_point=(2*x+8)/x')

+x0=5;

+while abs(x0-fx(x0))>0.5*10^(-2)

+  x0=fx(x0);

+end

+disp(x0,'root is :')

+

+//third way x=(x^2-8)/2

+

+format('v',10)

+funcprot(0);

+deff('[fixed_point]=fx(x)','fixed_point=(x^2-8)/2')

+x0=5;

+for i=1:5

+  x0=fx(x0);

+  disp(x0,'value is :')

+end

+disp(x0,'As you can see that the root is not converging.So this method is not applicable.')

+