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authorpriyanka2015-06-24 15:03:17 +0530
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+//Chapter-7,Example7_3_3,pg 7-7
+
+Ho=6.5*10^4 //critical field at absolute zero
+
+Tc=7.18 //critical temperature
+
+T=4.2 //temperature
+
+r=0.5*10^-3 //radius of lead wire
+
+Hc=Ho*(1-(T/Tc)^2)
+
+Ic=2*%pi*r*Hc
+
+printf("\ncritical current for wire Ic = %.2f Amperes\n",Ic)