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authorpriyanka2015-06-24 15:03:17 +0530
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+//Chapter-2,Example2_2_6,pg 2-12
+
+a=2*10^-6 //width of slit
+
+n=1 //for first minimum
+
+wavelength=6500*10^-10 //wavelength of light
+
+angle=asind(n*wavelength/a) //angular seperation
+
+printf('\nThe half angular width of a principal maximum is angle =%.2f degrees\n',angle)