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+// Exa 6.2

+clc;

+clear;

+close;

+// Given data

+V=38.4;// in volt

+I=0.4;// in amp

+ammeterRange= 1;// in amp

+voltmeterRange= 50;// in volt

+inst_acc= 1/2;// instrument accurcy in %

+R= 100;// resistance in ohm

+

+R_A= 2.5;// in ohm

+R_V= 6000;// in ohm

+Rx= sqrt(R_A*R_V);// in ohm

+disp(Rx,"Value of unknown resistance in ohm")

+disp("Since the unknown resistance is of value smaller than "+string(Rx)+" ohm, the voltmeter should be connected directly across the unknown resistance as it will give more accurate result")

+Rm= V/I;// in ohm

+Rx= V/(I*(1-V/(I*R_V)));// in ohm

+ErrorAmmeter= inst_acc*ammeterRange/R;// Error in ammeter reading in amp

+ErrorVoltmeter= inst_acc*voltmeterRange/R;// Error in voltmeter reading in volt

+// Percentage error at 0.4 A reading 

+E1= ErrorAmmeter/0.4*100;//in %

+// Percentage error at 38.4 V reading 

+E2= ErrorVoltmeter/38.4*100;//in %

+//Error due to ammeter and voltmeter

+E= sqrt(E1^2+E2^2);

+//Absolute error due to ammeter and voltmeter

+Error_ammeter_voltmeter= E/R*Rx;// in pos and neg

+disp(Error_ammeter_voltmeter,"Absolute error due to ammeter and voltmeter in ohm")

+disp("So the resistance is specified as "+string(Rx-Error_ammeter_voltmeter)+" to "+string(Rx+Error_ammeter_voltmeter));