initial commit / add all books

10 files changed, 163 insertions, 0 deletions

diff --git a/1823/CH5/EX5.1/SolEx5_1.sce b/1823/CH5/EX5.1/SolEx5_1.sce
new file mode 100755
index 000000000..e1e447d38
--- /dev/null
+++ b/1823/CH5/EX5.1/SolEx5_1.sce
@@ -0,0 +1,7 @@
+//find its leakage current at 90 degree C.

+//Example 5.1 page no 143

+clear

+clc

+Icbo=(500*(2^((90-25)/10)))/1000

+printf("\n The value of Icbo=%0.3f mA" ,Icbo)

+

diff --git a/1823/CH5/EX5.11/SolEx5_11.sce b/1823/CH5/EX5.11/SolEx5_11.sce
new file mode 100755
index 000000000..bba036030
--- /dev/null
+++ b/1823/CH5/EX5.11/SolEx5_11.sce
@@ -0,0 +1,20 @@
+//(a) Find the exact change in ICQ. (b) Predict the new value of ICQ using stability-factor analysis.

+//Example 5.11 page no 148

+clear

+clc

+Vbb=6

+Vbeq1=0.7

+Icbo1=0.5

+Rb=50

+Re=1

+B=75//Beta

+Icq1=((Vbb-Vbeq1+Icbo1*(0.5*51*10^-3))/((Rb*10^3/B)+Re*10^3))*10^3

+printf("\n The value of Icq1=%0.3f mA" ,Icq1)

+Icbo2=(Icbo1*10^-6*2^2)*10^6

+printf("\n The value of Icbo=%0.3f mA" ,Icbo2)

+Vbeq=(-2*10^-3)*20

+printf("\n The value of Vbeq=%0.3f V" ,Vbeq)

+Vbeq2=Vbeq1+Vbeq

+printf("\n The value of Vbeq2=%0.3f V" ,Vbeq2)

+Icq2=((Vbb-Vbeq2+Icbo2*(2*51*10^-3))/((Rb*10^3/B)+Re*10^3))*10^3

+printf("\n The value of Icq2=%0.3f mA" ,Icq2)

diff --git a/1823/CH5/EX5.16/SolEx5_16.sce b/1823/CH5/EX5.16/SolEx5_16.sce
new file mode 100755
index 000000000..14e6e9997
--- /dev/null
+++ b/1823/CH5/EX5.16/SolEx5_16.sce
@@ -0,0 +1,12 @@
+//Find an expression for ICQ at any temperature.

+//Example 5.16 page no 150

+clear

+clc

+B=50//beta

+Vee=5

+Vbeq1=0.7

+T2=125

+Re=3*10^3

+Icbo1=0.5//*10^-6

+Icq2=(((B+1)/B)*((Vee-Vbeq1+0.002*(T2-25))/Re)+(2^((T2-25)/10))*Icbo1*10^-6)*10^3

+printf("\n The value of Icq2=%0.3f mA" ,Icq2)

diff --git a/1823/CH5/EX5.19/SolEx5_19.sce b/1823/CH5/EX5.19/SolEx5_19.sce
new file mode 100755
index 000000000..7e353b9a6
--- /dev/null
+++ b/1823/CH5/EX5.19/SolEx5_19.sce
@@ -0,0 +1,15 @@
+//Determine a first-order approximation for the change in ICQ1

+//Example 5.19 page no 152

+clear

+clc

+B=75//beta

+Rb=454.5        //kΩ

+Icbo=0.2*10^-6

+Vbb=1.818

+Vbeq=0.7

+Re=90

+deltaRe=110-90

+Sre=((B*Rb*Icbo-B^2*(Vbb-Vbeq+Icbo*Rb))/((Rb+B*Re)^2))*10^4

+printf("\n The value of Sre=%0.3f * 10^-4 A/Ohm" ,Sre)

+Icq=(Sre*deltaRe)/10

+printf("\n The value of Icq=%0.3f * 10^-4 mA" ,Icq)

diff --git a/1823/CH5/EX5.25/SolEx5_25.sce b/1823/CH5/EX5.25/SolEx5_25.sce
new file mode 100755
index 000000000..722b0722c
--- /dev/null
+++ b/1823/CH5/EX5.25/SolEx5_25.sce
@@ -0,0 +1,13 @@
+//(a) Find the range of values of IDQ that could be expected in using this FET. (b) Find the corresponding range of VDSQ. (c) Comment on the

+//desirability of this bias arrangement.

+//Example 5.25 page no 156

+clear

+clc

+Vdd=15

+Idqmax=5.5

+Idqmin=1.3

+Rd=2.5          //kΩ

+Vdsqmax=Vdd-Idqmax*Rd

+Vdsqmin=Vdd-Idqmin*Rd

+printf("\n The value of Vdsqmax=%0.3f V" ,Vdsqmax)

+printf("\n The value of Vdsqmin=%0.3f V" ,Vdsqmin)

diff --git a/1823/CH5/EX5.26/SolEx5_26.sce b/1823/CH5/EX5.26/SolEx5_26.sce
new file mode 100755
index 000000000..afe1a5561
--- /dev/null
+++ b/1823/CH5/EX5.26/SolEx5_26.sce
@@ -0,0 +1,14 @@
+//(a) Find the range of IDQ that can be expected. (b) Find the range of VDSQ that can be expected. (c) Discuss

+//the idea of reducing IDQ variation by increasing the value of RS.

+//Example 5.26 page no 157

+clear

+clc

+Vdd=24      //V

+Idqmax=2.5

+Idqmin=1.2

+Rs=1        //kΩ

+Rd=3        //kΩ

+Vdsqmax=Vdd-Idqmax*(Rs+Rd)

+Vdsqmin=Vdd-Idqmin*(Rs+Rd)

+printf("\n The value of Vdsqmax=%0.3f V" ,Vdsqmax)

+printf("\n The value of Vdsqmin=%0.3f V" ,Vdsqmin)

diff --git a/1823/CH5/EX5.28/SolEx5_28.sce b/1823/CH5/EX5.28/SolEx5_28.sce
new file mode 100755
index 000000000..251d95378
--- /dev/null
+++ b/1823/CH5/EX5.28/SolEx5_28.sce
@@ -0,0 +1,14 @@
+//a) Find the range of IDQ that can be expected if R1 ¼ 1M
 and R2 ¼ 3M
. (b) Find the range of IDQ that can be expected if R1 ¼ 1M


+//and R2 = 7M
. (c) Discuss the significance of the results of parts a and b.

+//Example 5.28 page no 159

+clear

+clc

+Vdd=24

+Idqmax=4

+Idqmin=2.8

+Rs=2        //MΩ

+Rd=1        //MΩ

+Vdsqmax=Vdd-Idqmax*(Rs+Rd)

+Vdsqmin=Vdd-Idqmin*(Rs+Rd)

+printf("\n The value of Vdsqmax=%0.3f V" ,Vdsqmax)

+printf("\n The value of Vdsqmin=%0.3f V" ,Vdsqmin)

diff --git a/1823/CH5/EX5.6/SolEx5_6.sce b/1823/CH5/EX5.6/SolEx5_6.sce
new file mode 100755
index 000000000..df9de9a27
--- /dev/null
+++ b/1823/CH5/EX5.6/SolEx5_6.sce
@@ -0,0 +1,25 @@
+//Find ICQ and VCEQ (a) for bet  50 and (b) for beta  100

+//Example 5.6 page no 145

+clear

+clc

+Vee=4               //v

+Vbeq=0.7            //v

+Rb=25*10^3             //kΩ

+b=50//Beta

+Re=2*10^3           //kΩ

+Icq=((Vee-Vbeq)/((Rb/b)+((b+1)/b)*Re))*1000

+printf("\n The value of Icq=%0.3f mA" ,Icq)

+Vcc=18          //v

+Rc=6            //kΩ

+Re=2//*10^3     //kΩ

+Vceq=Vcc+Vee-(Rc+((b+1)/b)*Re)*Icq          //v

+printf("\n For beta=100")

+printf("\n The value of Vceq=%0.3f V" ,Vceq)

+printf("\n For beta=100")

+b=100

+Re=2*10^3

+Icq=((Vee-Vbeq)/((Rb/b)+((b+1)/b)*Re))*1000

+printf("\n The value of Icq=%0.3f mA" ,Icq)

+Re=2//*10^3

+Vceq=Vcc+Vee-(Rc+((b+1)/b)*Re)*Icq

+printf("\n The value of Vceq=%0.3f V" ,Vceq)

diff --git a/1823/CH5/EX5.8/SolEx5_8.sce b/1823/CH5/EX5.8/SolEx5_8.sce
new file mode 100755
index 000000000..250996242
--- /dev/null
+++ b/1823/CH5/EX5.8/SolEx5_8.sce
@@ -0,0 +1,32 @@
+//Find ICQ; IBQ, and VCEQ if (a)  beta 50 and (b) beta ¼ 100.

+//Example 5.8 page no 146

+clear

+clc

+Vcc=15              //v

+Vee=4               //v 

+Vbeq=0.7            //v

+b=50//Beta

+Re=3*10^3               //kΩ

+Rc=7                    //kΩ

+Ieq=(Vee-Vbeq)/Re*1000

+printf("\n For beta=50")

+printf("\n The value of Ieq=%0.3f mA" ,Ieq)

+Icq=(b/(b+1))*Ieq

+printf("\n The value of Icq=%0.3f mA" ,Icq)

+Ibq=Icq/b

+printf("\n The value of Ibq=%0.3f mA" ,Ibq)

+Vee=5

+Re=3//*10^3

+Vceq=Vcc+Vee-(Ieq*Re)-(Icq*Rc)

+printf("\n The value of Vceq=%0.3f V" ,Vceq)

+printf("\n For beta=100")

+b=100

+printf("\n The value of Ieq=%0.3f mA" ,Ieq)

+Icq=(b/(b+1))*Ieq

+printf("\n The value of Icq=%0.3f mA" ,Icq)

+Ibq=Icq/b

+printf("\n The value of Ibq=%0.3f mA" ,Ibq)

+Vee=5

+Re=3//*10^3

+Vceq=Vcc+Vee-(Ieq*Re)-(Icq*Rc)

+printf("\n The value of Vceq=%0.3f V" ,Vceq)

diff --git a/1823/CH5/EX5.9/SolEx5_9.sce b/1823/CH5/EX5.9/SolEx5_9.sce
new file mode 100755
index 000000000..f3e6f4dd2
--- /dev/null
+++ b/1823/CH5/EX5.9/SolEx5_9.sce
@@ -0,0 +1,11 @@
+//Example 5.9 page no 147

+clear

+clc

+Vcc=15

+Vee=4

+Vbeq=0.7

+Rb=500

+Sb=((Vcc-Vbeq)/Rb)*10^3

+printf("\n The value of Sb=%0.3f " ,Sb)

+Icq=(Sb*(100-50))/1000

+printf("\n The value of Icq=%0.3f mA" ,Icq)