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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /1823/CH1/EX1.7/SolEx1_7.sce | |
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Diffstat (limited to '1823/CH1/EX1.7/SolEx1_7.sce')
-rwxr-xr-x | 1823/CH1/EX1.7/SolEx1_7.sce | 17 |
1 files changed, 17 insertions, 0 deletions
diff --git a/1823/CH1/EX1.7/SolEx1_7.sce b/1823/CH1/EX1.7/SolEx1_7.sce new file mode 100755 index 000000000..9249f1491 --- /dev/null +++ b/1823/CH1/EX1.7/SolEx1_7.sce @@ -0,0 +1,17 @@ +
+//find the Thevenin equivalent for the network to the left of terminals a; b.
+//Solved Example 1.7
+//page no 19
+clear
+clc
+printf("\n find the TheĀ“venin equivalent for the network to the left of terminals a; b.")
+V1=10//V
+V2=15//V
+R1=4//ohm
+R2=6//ohm
+I=(V1-V2)/(R1+R2)
+printf("\n The value of I is =%0.2f A",I)
+Vth=V1-I*R1
+printf("\n The value of Thevenin Equivalent voltage=%0.2f V",Vth)
+Zth=(R1*R2)/(R1+R2)
+printf("\n The value of Thevenin Impedance =%0.2f ohm",Zth)
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