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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /1823/CH1/EX1.11 | |
| download | Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.gz Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.bz2 Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.zip | |
initial commit / add all books
Diffstat (limited to '1823/CH1/EX1.11')
| -rwxr-xr-x | 1823/CH1/EX1.11/SoluEx1_11.sce | 15 |
1 files changed, 15 insertions, 0 deletions
diff --git a/1823/CH1/EX1.11/SoluEx1_11.sce b/1823/CH1/EX1.11/SoluEx1_11.sce new file mode 100755 index 000000000..55e9e28d8 --- /dev/null +++ b/1823/CH1/EX1.11/SoluEx1_11.sce @@ -0,0 +1,15 @@ +//Solved Example 1.11 Page no 14
+//Find the half-cycle average value of the current through a resistance R
+clear
+clc
+printf("\n Find the Norton equivalent current IN and admittance YN")
+Va=4.0//V
+a=0.25//A/V
+R1=2//ohm
+R2=3//ohm
+I=2
+Zth=5
+Ia=(Va/(R1+R2))+((R1*I)/(R1+R2))
+Yn=1/Zth
+printf("\n Norton equivalent current IN is = %.2f V",Ia)
+printf("\n admittance YN is = %.2f Ohm",Yn)
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