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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /1820/CH3/EX3.3/Example3_3.sce | |
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| -rwxr-xr-x | 1820/CH3/EX3.3/Example3_3.sce | 30 |
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diff --git a/1820/CH3/EX3.3/Example3_3.sce b/1820/CH3/EX3.3/Example3_3.sce new file mode 100755 index 000000000..1d5daec8b --- /dev/null +++ b/1820/CH3/EX3.3/Example3_3.sce @@ -0,0 +1,30 @@ +// ELECTRIC POWER TRANSMISSION SYSTEM ENGINEERING ANALYSIS AND DESIGN
+// TURAN GONEN
+// CRC PRESS
+// SECOND EDITION
+
+// CHAPTER : 3 : FUNDAMENTAL CONCEPTS
+
+// EXAMPLE : 3.3 :
+clear ; clc ; close ; // Clear the work space and console
+
+// GIVEN DATA
+// For case (c)
+I_normal = 1000 ; // Normal full load current in Ampere
+
+// CALCULATIONS
+// For case (a) equation is (1.5pu)*I_rated = (2 pu)*I_normal
+// THEREFORE
+// I_rated = (1.333pu)*I_normal ; // Rated current in terms of per unit value of the normal load current
+
+// For case (b)
+Mvar = (1.333)^2 ; // Increase in Mvar rating in per units
+
+// For case (c)
+I_rated = (1.333)*I_normal ; // Rated current value
+
+// DISPLAY RESULTS
+disp("EXAMPLE : 3.3 : SOLUTION :-") ;
+printf("\n (a) Rated current , I_rated = (1.333 pu)*I_normal \n") ;
+printf("\n (b) Mvar rating increase = %.2f pu \n",Mvar) ;
+printf("\n (c) Rated current value , I_rated = %.f A \n",I_rated) ;
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