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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /1820/CH12/EX12.3 | |
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-rwxr-xr-x | 1820/CH12/EX12.3/Example12_3.sce | 44 |
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diff --git a/1820/CH12/EX12.3/Example12_3.sce b/1820/CH12/EX12.3/Example12_3.sce new file mode 100755 index 000000000..0689f6586 --- /dev/null +++ b/1820/CH12/EX12.3/Example12_3.sce @@ -0,0 +1,44 @@ +// ELECTRIC POWER TRANSMISSION SYSTEM ENGINEERING ANALYSIS AND DESIGN
+// TURAN GONEN
+// CRC PRESS
+// SECOND EDITION
+
+// CHAPTER : 12 : CONSTRUCTION OF OVERHEAD LINES
+
+// EXAMPLE : 12.3 :
+clear ; clc ; close ; // Clear the work space and console
+
+// GIVEN DATA
+a = 45 ; // OH line to be bulit on wood poles in ft
+b = 6.5 ; // Ground depth in ft
+c = 1 ; // Top cross-arm below pole top in ft
+d = 3 ; // Lower cross-arm below pole top in ft
+m_t = 0.6861 ; // Transverse wind load on top cross-arm in lb/ft
+m_l = 0.4769 ; // Transverse wind load on lower cross-arm in lb/ft
+u_s = 8000 ; // Ultimate strength of wood pole in lb/sq.in
+sf = 2 ; // Safety factor
+span_avg = 250 ; // Average span in ft
+p = 9 ; // Transverse wind load on wood poles in clb/sq.ft
+
+// CALCULATIONS
+h_1j = a - b - c ; // Moment arms for top arm in ft
+h_2j = a - b - d ; // Moment arms for top arm in ft
+M_tc1 = 1 * 4* m_t * span_avg * h_1j ; // Total bending moment for top arm in lb-ft
+M_tc2 = 1 * 4* m_l * span_avg * h_2j ; // Total bending moment for lower arm in lb-ft
+M_tc = M_tc1 + M_tc2 ; // Total bending moment for both cross-arms together in lb-ft
+S = u_s/sf ; // Allowable max fiber stress in pounds per sq.inch
+c_pg = ( M_tc/( 2.6385*10^-4*S ) )^(1/3) ; // circumference of pole at ground line in inch
+
+c_pt = 22 ; // From proper tables , for 8000 psi ,
+h_ag = a - b ; // Height of pole above ground in ft
+d_pg = c_pg/(%pi) ; // circumference of pole at ground line in inches
+d_pt = c_pt/(%pi) ; // circumference of pole at pole top in inches
+M_gp = (1/72)*p *(h_ag^2)*(d_pg + 2*d_pt) ; // Bending moment due to wind on pole in pound ft . using equ 12.9
+M_T = M_tc + M_gp ; // Total bending moment due to wind on conductor & pole
+c_pg1 = (M_T/( 2.6385 * 10^-4 * S ) )^(1/3) ; // using equ 12.11
+
+// DISPLAY RESULTS
+disp("EXAMPLE : 12.3 : SOLUTION :-") ;
+printf("\n Minimum required pole circumference at the ground line , c = %.1f in \n",c_pg1) ;
+printf("\n Therefore , the nearest standard size pole,which has a ground-line circumference larger than c = %.1f in , has to be used \n",c_pg1) ;
+printf("\n Therefore required pole circumference at the ground line to be used is , c = %.f inch \n",c_pg1) ;
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