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diff --git a/182/CH9/EX9.3/9_3.txt b/182/CH9/EX9.3/9_3.txt
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+

+3.V peak-peak of wave from A=1.20 V

+  frequency of wave form A=1666.666667 Hz

+  V peak-peak of wave from B=0.48 V

+  frequency of wave form B=1428.571429 Hz

+  phase difference=60 degree 

diff --git a/182/CH9/EX9.3/example9_3.sce b/182/CH9/EX9.3/example9_3.sce
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+// to find the amplitude,frequency and the phase difference b/w two waveforms in the figure 9-20

+// example 9-3 in page 256

+clc;

+//Data Given

+x=['A' 'B'];

+V=200D-3;// volatge/division=200mV

+T=0.1D-3;//time/division=0.1ms

+one_cycle=360;// one cycle=360 degree

+Vd=[6 2.4];// vertical divisions of A and B respectively

+Hd=[6 7];// horizontal divisions of A and B respectively

+//calculation

+for n=1:2

+    Vp=Vd(n)*V;// V peak-to-peak

+    Tp=T*Hd(n);// time period

+    f=1/Tp;//frequency

+    printf("V peak-peak of wave from %c=%.2f V\n",x(n),Vp);

+    printf("frequency of wave form %c=%.0f Hz\n",x(n),f);

+end

+phase_diff=Hd(2)-Hd(1);

+phase_diff=one_cycle*phase_diff/6;// here one cycle makes 6 horizontal divisions

+printf("phase difference=%d degree",phase_diff);

+//result

+//V peak-peak of wave from A=1.20 V

+//frequency of wave form A=1667 Hz

+//V peak-peak of wave from B=0.48 V

+//frequency of wave form B=1429 Hz

+//phase difference=60 degree