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authorprashantsinalkar2017-10-10 12:27:19 +0530
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+clc
+clear
+//INPUT DATA
+t1=35;//dry bulb temperature in Degree c
+x1=0.8;//realtive humidity in percentage
+t2=15;//Apparatus dew point in Degree c
+t4=25;//dry bulb temperature in Degree c
+V1=200;//Quantity of moist air in m^3/min
+x=0.3;//bypass factor
+ps1=42.16;//Saturation pressure in mm Hg
+p=760;//pressure in mm of Hg
+Ra=287.3;//gas constant
+cp=1.005;//specific pressure
+ps2=12.77;//Saturation pressure in mm Hg
+ps4=23.74;//Saturation pressure in mm Hg
+
+//CALCULATIONS
+pv1=x1*ps1;//Saturation pressure in mm Hg
+w1=0.622*(pv1/(p-pv1));//Specific humidity in kg w.v./kg d.a
+t3=(x*(t1-t2))+t2;//dry bulb temperature in Degree c
+h1=cp*t1+w1*(2500+1.88*t1);//Enthalpy of air per kg of dry air in kJ/kg d.a.
+w2=0.622*(ps2/(p-ps2));//Specific humidity in kg w.v./kg d.a
+w3=x*(w1-w2)+w2;//Specific humidity in kg w.v./kg d.a
+h3=cp*t3+w3*(2500+1.88*t3);//Enthalpy of air per kg of dry air in kJ/kg d.a.
+h4=cp*t4+w3*(2500+1.88*t4);//Enthalpy of air per kg of dry air in kJ/kg d.a.
+v1=Ra*(273+t1)/((p-pv1)*133.5);//volume
+ma=V1/v1;//Amount of air added in kg d.a./min
+Qc=ma*(h1-h3)/210;//Capacity of cooling coil in TR
+Qh=ma*(h4-h3)/60;//Capacity of heating coil in kW
+mw=ma*(w1-w3);//Quantity of water removed in kg w.v./min
+pv4=w3*p/1.01611;//Saturation pressure in mm Hg
+x4=(pv4/ps4)*100;//realtive humidity in percentage
+
+//OUTPUT
+printf('(a)Capacity of cooling coil is %3.2f TR \n (b)Capacity of heating coil is %3.2f kW \n(c)Quantity of water removed is %3.4f kg w.v./min \n (d)realtive humidity is %3.2f percentage',Qc,Qh,mw,x4)