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authorprashantsinalkar2017-10-10 12:27:19 +0530
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+clc
+clear
+//INPUT DATA
+n=1.35;//for cylinders
+p1=1;//pressure in bar
+v1=1;//volume in m^3
+p2=7;//pressure in bar
+nm=0.85;//mechanical efficiency in percentage
+nt=0.9;//Turbine efficiency in percentage
+N=300;//speed in rpm
+
+//CALCULATIONS
+//(a)single acting cylinder
+ip1=((n/(n-1))*p1*10^2*v1*(((p2/p1)^((n-1)/n))-1))/60;//indicated power in kW
+bp1=ip1/nm;//brake power in kW
+mp1=bp1/nt;//motor power in kW
+d1=((v1*4/(1.5*N*3.14))^(1/3))*100;//cylinder bore in single acting cylinder in cm
+l1=(1.5)*d1;//stroke in cm
+
+//Double acting cylinder
+d2=((v1*4/(1.5*N*2*3.14))^(1/3))*100;//cylinder bore in double acting cylinder
+l2=1.5*d2;//stroke in cm
+
+//OUTPUT
+printf('(a)Single acting cylinder \n (i)Indicated power is %3.3f kW \n (ii)Power input to the compressor %3.3f kW \n (iii) cylinder bore in single acting cylinder is %3.4f cm \n stroke is %3.2f cm \n',ip1,mp1,d1,l1)
+
+printf('(a)Double acting cylinder \n (i)Indicated power is %3.3f kW \n (ii)Power input to the compressor %3.3f kW \n (iii) cylinder bore in double acting cylinder is %3.4f cm \n stroke is %3.2f cm',ip1,mp1,d2,l2)
+