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authorprashantsinalkar2017-10-10 12:27:19 +0530
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+clc
+clear
+//INPUT DATA
+p1=100;//pressure in bar
+p2=10;//pressure in bar
+p3=0.1;//pressure in bar
+T1=500;//Temperature of turbine in Degree C
+T2=450;//Temperature of turbine in Degree C
+h1=3240.9;//Enthalpy in kJ/kg
+h4=3370.7;//Enthalpy in kJ/kg
+h3=2776.2;//Enthalpy in kJ/kg
+h10=762.6;//Enthalpy in kJ/kg
+h6=191.8;//Enthalpy in kJ/kg
+h9=2584.7;//Enthalpy in kJ/kg
+S1=6.419;//Entropy in kJ/kg.K
+S4=7.618;//Entropy in kJ/kg.K
+S3=6.5828;//Entropy in kJ/kg.K
+S10=2.1382;//Entropy in kJ/kg.K
+S6=0.649;//Entropy in kJ/kg.K
+S9=8.15;//Entropy in kJ/kg.K
+nt=0.8;//Turbine efficiency in percentage
+v6=0.001001;//Specific volume in m^3/kg
+P=100000;//power output in kW
+
+
+//CALCULATIONS
+x2=((S1-S10)/(S3-S10));//quality of steam
+h2=h10+(x2*(h3-h10));//Enthalpy in kJ/kg
+h21=h1-(nt*(h1-h2));//Enthalpy in kJ/kg
+x5=((S4-S6)/(S9-S6));//quality of steam
+h5=h6+(x5*(h9-h6));//Enthalpy in kJ/kg
+h51=h4-(nt*(h4-h5));//Enthalpy in kJ/kg
+Wt=(h1-h21)+(h4-h51);//Turbine work in kJ/kg
+h7=h6+(v6*(p1-p3)*100);//Enthalpy in kJ/kg
+Wp=(h7-h6);//Pump work in kJ/kg
+Qs=(h1-h7)+(h4-h21);//heat supplied in kJ/kg
+nRi=((Wt-Wp)/Qs)*100;//Cycle efficiency
+m=P/(Wt-Wp);//mass flow rate in kg/s
+Qr=(h51-h6)*m;//rate of heat transfer from condenser in kW
+
+//OUTPUT
+printf('(i)Thermal efficiency is %3.2f percent \n (ii)Mass flow rate is %3.2f kg/s \n (iii)Rate of heat transfer from the condenser %3.2f kW',nRi,m,Qr)
+