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authorprashantsinalkar2017-10-10 12:27:19 +0530
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+clc
+clear
+//INPUT DATA
+cp=1.005;//specific pressure
+cv=0.718;//specific volume
+R=0.287;//gas constant
+p1=100;//Pressure in kPa
+t1=300;//temperature in K
+g=1.35//constant
+t3=1000;//temperature in K
+nc=0.85;//compressor efficiency in percentage
+nt=0.9;//Thermal efficiency in percentage
+
+
+//CALCULATIONS
+Rp=(t3/t1)^(g/(g-1));//maximum pressure ratio
+Rpo=sqrt(Rp*nc*nt);//Pressure ratio for maximum work
+t2=t1*(Rpo)^((g-1)/g);//temperature in K
+t21=t1+((t2-t1)/nc);//temperature in K
+t4=t3/(Rpo^((g-1)/g));//temperature in K
+t41=t3-(nt*(t3-t4));//temperature in K
+nbt=(((t3-t41)-(t21-t1))/(t3-t21))*100;//Thermal efficiency in percentage
+
+//OUTPUT
+printf('(i)Pressure ratio for maximum work is %3.2f \n (ii)Thermal efficiency is %3.2f percentage ',Rpo,nbt)
+
+
+
+