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author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
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committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /1808/CH2/EX2.21/Chapter2_Example21.sce | |
parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
Diffstat (limited to '1808/CH2/EX2.21/Chapter2_Example21.sce')
-rw-r--r-- | 1808/CH2/EX2.21/Chapter2_Example21.sce | 13 |
1 files changed, 13 insertions, 0 deletions
diff --git a/1808/CH2/EX2.21/Chapter2_Example21.sce b/1808/CH2/EX2.21/Chapter2_Example21.sce new file mode 100644 index 000000000..8cb5a22c3 --- /dev/null +++ b/1808/CH2/EX2.21/Chapter2_Example21.sce @@ -0,0 +1,13 @@ +clc
+clear
+//INPUT DATA
+//H2+ 0.5(O2+3.773 N2)= H2O+1.887 N2 ;//CHEMICAL EQUATION
+//22.3 H2 +18.606 O2 +70.2 N2 = 22.3 H2O+ 7.44 O2+70.2 N2 ;//EXHAUST GASES CHEMICAL EQUATION
+
+//CALCULATIONS
+xs=2*1/(0.5*32+0.5*3.773*28);//air fuel ratio From the combustion equation
+xa=(1*2)/(0.8343*32+3.148*28);//air fuel ratio From the combustion equation
+x=xa/xs;//Equivalent ratio
+
+//OUTPUT
+printf('Equivalent ratio is %3.3f',x)
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