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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+clc
+c=30
+b=15
+a=10
+Ka=0.3872 // from table 13.8
+H=4
+G=15
+Pa=G*H^2*Ka/2
+printf('The active force per unit length Pa = %f kN/m\n',Pa)
+printf(' The resultant will act at a vertical distance equal to H/3 = 4/3 = 1.33 m above \n the bottom of the wall and will be inclined at an angle of 15to the back face of the wall.')