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+//Chapter-1, Illustration 11, Page 24
+//Title: Fuels and Combustion
+//=============================================================================
+clc
+clear
+
+//INPUT DATA
+H2=0.5;//Percentage composition of H2 by volume
+CO2=0.1;//Percentage composition of CO2 by volume
+CO=0.05;//Percentage composition of CO by volume
+CH4=0.25;//Percentage composition of CH4 by volume
+N2=0.1;//Percentage composition of N2 by volume
+pCO2=8;//Percentage volumetric analysis of CO2
+pO2=6;//Percentage volumetric analysis of O2
+pN2=86;//Percentage volumetric analysis of N2
+
+
+//CALCULATIONS
+v=(2.38*(H2+CO))+(9.52*CH4);//Volume of air required for complete combustion in (m^3)
+vN2=v*0.79;//Volume of nitrogen in the air in m^3
+a=CO+CH4+CO2;//CO2 formed per m^3 of fuel gas burnt
+b=vN2+N2;//N2 formed per m^3 of fuel gas burnt
+vt=a+b;//Total volume of dry flue gas formed in m^3
+ve=(pO2*vt)/(21-pO2);//Excess air supplied in m^3
+V=v+ve;//Total quantity of air supplied in m^3
+
+//OUTPUT
+mprintf('Air-fuel ratio by volume is %3.3f:1',V)
+
+
+
+
+//==============================END OF PROGRAM=================================