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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+ //EXAMPLE-2.97 PG NO-140
+N1=500; //NUMBER OF TURN
+N22=1500;
+N12=500
+Q1=0.6*10^-3; //FLUX OF COIL
+I1=5; //CURRENT
+Q12=0.3*10^-3;
+L1=(N1*Q1)/I1
+K=Q12/Q1;
+L2=(N22/N12)*L1;
+M=K*((L1*L2)^0.5);
+disp('i) L1 = '+string (L2)+' ');
+disp('ii) K = '+string (K)+' H');
+disp('iii) L2 = '+string (L2)+' H');
+disp('i) M = '+string (M)+' H ');